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Start your free trialHolden Glass
6,077 PointsNot sure how it wants me to return the data
I have played around with this and I don't know how it wants me to output the data. In the example it just has a single datetime and I don't know how to get it like that. I am sure as soon as someone posts an answer for this question I'll get it but until then, I'm kinda stuck.
import datetime
starter = datetime.datetime(2015, 10, 21, 16, 29)
# Remember, you can't set "years" on a timedelta!
# Consider a year to be 365 days.
## Example
# time_machine(5, "minutes") => datetime(2015, 10, 21, 16, 34)
def time_machine(number, string):
if string == 'years':
the_days = 365 * number
return datetime.datetime(starter + datetime.timedelta(days=the_days))
elif string == 'days':
return datetime.datetime(starter + datetime.timedelta(days=number))
elif string == 'hours':
return datetime.datetime(starter + datetime.timedelta(hours=number))
elif string == 'minutes':
return datetime.datetime(starter + datetime.timedelta(minutes=number))
1 Answer
Steven Parker
231,269 PointsYou're doing more work than you should.
Remember, if you already have a datetime (like starter), and you add a timedelta to it, the result is also a datetime. You can return that directly.
Holden Glass
6,077 PointsHolden Glass
6,077 PointsI tried to do that to. I would just take away the datetime.datetime at the beginning right?
Steven Parker
231,269 PointsSteven Parker
231,269 PointsYes, and then you can remove the parentheses around the expression.