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Start your free trialTimothy Grindall
7,843 PointsNot seeing variable
So I put the ajaxurl variable between script tags like it said in the instructions but its not seeing it for some reason. It says: 'The script tag should have a variable named "ajaxurl" with a value assigned to it.' Anybody know what's going on?
<?php
function my_plugin_frontend_scripts() {
wp_enqueue_style('my_plugin_frontend_css', plugins_url('my-plugin/css/front-end.css'));
wp_enqueue_script('my_plugin_frontend_js', plugins_url('my-plugin/js/front-end.js'), array('jquery'), '', true);
}
add_action('wp_enqueue_scripts', 'my_plugin_frontend_scripts');
function my_plugin_enable_ajax() { ?>
<script>
var ajaxurl = admin_url('admin-ajax.php');
</script>
<?php }
?>
1 Answer
Rich Edwards
4,589 PointsI had trouble with this step, too.
You're close.
The problem you are having is that the admin_url function is a php function--not a javascript function. You need to drop back into php to use that function in order to declare the javascript variable.
If you need more help, go back and watch the first video on ajax calls starting around 3:30.