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4,175 Pointsnot running
defined .join() but showing error
available = "banana split;hot fudge;cherry;malted;black and white"
sundaes = available.split(";")
menu ="Our available flavors are: {}."
display_menu =available.join(",")
1 Answer
Steven Parker
231,248 PointsHere's a few hints:
- to create display_menu, you will need to reference sundaes, not available
- join is a string method that takes an iterable argument, unlike split which is the opposite
- once you have properly created display_menu you will need to use it with format
- remember to put the final result back in menu