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C# C# Objects Inheritance Throwing Exceptions

Posted by Daniel Kolb
Daniel Kolb
10,172 Points

Not really sure what to do here. any help

I'm confused with how to format the syntax of try and catch clauses

Program.cs 
if (!(int value < 0 || int value > 20))
{
    throw new System.Exception();
}

try
{
    value = int.Parse(Console.ReadLine());

Console.WriteLine(string.Format("You entered {0}",value));
}
catch(Exception)
{

}

1 Answer

Steven Parker
Steven Parker
231,198 Points
Steven Parker
Steven Parker
231,198 Points

You're over-thinking this. The challenge is just to create the code to throw the exception, you won't need to use "try" or "catch" here. A few more hints:

  • you code needs to go between the assignment and the output
  • since the variable has already been declared, you won't need the "int" keywords
  • recheck the test logic, the inversion is not needed
Steven Parker
Steven Parker
231,198 Points
Steven Parker
Steven Parker
231,198 Points

Daniel Kolb — Did this fix your issue? You can mark a question solved by choosing a "best answer".
And happy coding!