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Start your free trialKennedi Armstrong
883 PointsNot printing "You win!..."
When I guess the word right, the "You win!..." message does not print.
import random
make a list of words
words = [ 'apple', 'banana', 'orange', 'coconut', 'strawberry', 'lime', 'grapefruit', 'lemon', 'kumquat', 'blueberry', 'melon' ]
while True: start = input("Press enter/return to start, or enter Q to quit") if start.lower() == 'q': break
# pick a random word
secret_word = random.choice(words)
bad_guesses = []
good_guesses = []
while len(bad_guesses) < 7 and len(good_guesses) != len(list(secret_word)):
# draw spaces
# draw guessed letters, spaces, and strikes
for letter in secret_word:
if letter in good_guesses:
print(letter, end='')
else:
print('_', end='')
print('')
print("Strikes: {}/7".format(len(bad_guesses)))
print('')
#take a guess
guess = input("Guess a letter: ").lower()
if len(guess) != 1:
print("You can only guess a single letter!")
continue
elif guess in bad_guesses or guess in good_guesses:
print("You've already guessed that letter!")
continue
elif not guess.isalpha():
print("You can only print letters!")
continue
if guess in secret_word:
good_guesses.append(guess)
if len(good_guesses) == len(list(secret_word)):
print("You win! The word was {}.".format(secret_word))
break
else:
bad_guesses.append(guess)
else:
print("You didn't guess it! My secret word was {}.".format(secret_word))
2 Answers
Jimmy Smutek
Python Web Development Techdegree Student 6,629 PointsI had the same issue, Kennedi.
The problem is that strings with multiple occurrences of a single letter will never make it past these lines:
good_guesses.append(guess)
if len(good_guesses) == len(list(secret_word)):
For example, if the string being evaluated is apple
, and on the first guess the user enters p
, then len(good_guesses)
will return 1, because we're only adding 1 occurrence of p
to the list. It makes sense on the surface, because there's only been 1 good guess thus far - but we're set up to fail because we're evaluating the amount of good guesses against the amount of letters in the target.
So, in the case of apple
, when the user reaches the end, good_guesses
will contain ['a' , 'p', 'l', 'e']
, len(good_guesses)
will return 4, while len(list(secret_word))
returns 5.
I'm sure there's a more elegant solution, but I was able to get around this by using count()
and then adding each occurrence of the letter to the list before counting.
# check for multiple occurrences of guess
occurrences = secret_word.count(guess)
# += will add each occurrence as a separate instance -
good_guesses += (guess * occurrences)
# now check the length
I couldn't get it to work with append()
, because it added the occurrences on as an additional list, but +=
seemed to do the trick. Here's my working code - hope this is helpful!
import random
# make a list of words
words = [
'apple',
'banana',
'coconut',
'strawberry'
]
while True:
start = input("Press enter to start, or Q to quit: ")
if start.lower() == 'q':
break
# pick a random word
secret_word = random.choice(words)
bad_guesses = []
good_guesses = []
while len(bad_guesses) < 7 and len(good_guesses) != len(list(secret_word)):
# draw spaces guessed letters and strikes
for letter in secret_word:
if letter in good_guesses:
print(letter, end='')
else:
print('_', end='')
print('')
print('Strikes: {}/7'.format(len(bad_guesses)))
print('')
# take guess
guess = input('Guess a letter: ').lower()
if len(guess) != 1:
print("You can only guess a single letter!")
continue
elif guess in bad_guesses or guess in good_guesses:
print("You already guessed that letter!")
continue
elif not guess.isalpha():
print("You can only guess letters!")
continue
if guess in secret_word:
# check for multiple occurrences of guess
occurrences = secret_word.count(guess)
print('Guess occurs {} times in the secret word'.format(occurrences))
# list.append() adds as a list, ie. ['a', ['pp'], 'l', 'e']
# += will add each occurrence as a separate instance -
good_guesses += (guess * occurrences)
# now check the length
if len(good_guesses) == len(list(secret_word)):
print("you win! The word was {}".format(secret_word))
break
else:
bad_guesses.append(guess)
else:
print("You did not guess it! My secret word was {}".format(secret_word))
Mike Wagner
23,559 PointsYou had a bit of a formatting issue in the way you posted your code in the question, so I'm not sure what your problem actually is. Once I took it into my private environment and adjusted the tabbing to what I thought would work I was left with a functional program that worked as expected. I'll add it here so you can have a look through it and try to find the difference that makes your version fail, but I'm guessing it has something to do with a misplaced or missing indent.
import random
words = [ 'apple', 'banana', 'orange', 'coconut', 'strawberry', 'lime', 'grapefruit', 'lemon', 'kumquat', 'blueberry', 'melon' ]
while True:
start = input("Press enter/return to start, or enter Q to quit")
if start.lower() == 'q': break
# pick a random word
secret_word = random.choice(words)
bad_guesses = []
good_guesses = []
while len(bad_guesses) < 7 and len(good_guesses) != len(list(secret_word)):
# draw spaces
# draw guessed letters, spaces, and strikes
for letter in secret_word:
if letter in good_guesses:
print(letter, end='')
else:
print('_', end='')
print('')
print("Strikes: {}/7".format(len(bad_guesses)))
print('')
#take a guess
guess = input("Guess a letter: ").lower()
if len(guess) != 1:
print("You can only guess a single letter!")
continue
elif guess in bad_guesses or guess in good_guesses:
print("You've already guessed that letter!")
continue
elif not guess.isalpha():
print("You can only print letters!")
continue
if guess in secret_word:
good_guesses.append(guess)
if len(good_guesses) == len(list(secret_word)):
print("You win! The word was {}.".format(secret_word))
break
else:
bad_guesses.append(guess)
else:
print("You didn't guess it! My secret word was {}.".format(secret_word))
Sam Bui
878 PointsSam Bui
878 PointsThank Jimmy, I have the same problem and I baffle to try to understand what wrong with my code. Your explaination just spot on :)