not much feedback on this one but please help on the if else steps to this quizz

Question

I seem to have made an error in logic somewhere on this as i want to be able to choose one path if a value is over 50 or another if it is equal or below. All this using class and methods
```first_class.py
class Student:
name = "Mark"
def feedback(self,grade):
    grade= 51
    if self.grade > 50:
         praise(self)
    else reassrance(self)

def praise(self):
    return "You inspire me, {}".format(self.name)

def reassurance(self):
    return "Chin up, {}. You'll get it next time!".format(self.name)
```

Jennifer Nordell · Answer

Hi there, @Mark Nembhard (https://teamtreehouse.com/marknembhard) ! There are a few things going on here. 
First, add the code for your new method to the bottom of the file.
The feedback method takes a grade argument at the time it is called/executed. The class itself has no grade attribute so there is no such thing as self.grade here. 
The else must be terminated with a colon and the following line indented under it.
You should be calling self.praise() and self.reassurance() without passing anything in
You are meant to return the strings produced by the praise and reassurance methods.
You have a typo in "reassurance" in your feedback method
Some pseudocode:
```py
def feedback(self,grade):
       if grade > 50:
           #  return the string produced by the praise method called on self
        else: 
           # return the string produced by the reassurance method called on self
```
Hope this helps! :sparkles:

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Mark Nembhard

Mark Nembhard

not much feedback on this one but please help on the if else steps to this quizz

1 Answer

Jennifer Nordell

Jennifer Nordell