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Java Java Basics Perfecting the Prototype Conditional ints

Posted by Agustinus Wellson Tengourtius
Agustinus Wellson Tengourtius
564 Points

Not able to find this syntax error. What actually when wrong with this code?

I have managed to put a condition to the code, however, it seems like it has a problem printing the "Your table is ready". Would you identify where is the syntax error. In the preview section, it shows that there is a problem in "console.printf"

Conditional.java 
int numberOfPeople = 3;
if(numberOfPeople<4){
  console.prinf("Your table is ready \n");
}

2 Answers

rudyrbastari
rudyrbastari
5,212 Points
rudyrbastari
rudyrbastari
5,212 Points

i see you write "printf" wrong. it should be "printf" not "prinf". (if this helps you, thx)

Agustinus Wellson Tengourtius
Agustinus Wellson Tengourtius
564 Points
Agustinus Wellson Tengourtius
Agustinus Wellson Tengourtius
564 Points

Alright thanks, Yeah its due to my carelessness. I tried to rewrite the code again and it works. Thanks for the help!

rudyrbastari
rudyrbastari
5,212 Points

your welcome.

rudyrbastari
rudyrbastari
5,212 Points

i hope you enjoy learning in treehouse