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kmxyckgzzc
395 Pointsnone
See that time variable? That's what time it currently is, at least for this test. But, when you submit your code, the time might change! I need you to make an if condition that sets store_open to True if time is in the store_hours list. Otherwise, if time isn't in store_hours, set store_open to False. You'll probably have to use if, else, and in to solve this one.
who can solve this challenge task please involving none? its in python basics , after tthe topic containment
time = 15
store_open = None
store_hours = [9, 10, 11, 12, 13, 14, 15, 16, 17, 18]
if time in store_hours:
3 Answers
Antonio De Rose
20,885 Pointsthe way you have started is perfectly correct. in the next line make it as below
store_open = True#make sure, this line is indented from the 1 above
else:
store_open = False
Antonio De Rose
20,885 PointsHi Eric,
It clearly, states it is an indentation error, are you sure, is that the right indentation for the else, the issue is in the else line, try solve it.
Thanks,
Anton
Eric Ward
4,198 PointsAh I was actually basing it of where you indented the 'else:' in your code, as seen above, which has else indented in. I fixed it though. Thanks!
Ramon Villarreal-Leal
4,764 Pointstime = 15
store_open = None store_hours = [9, 10, 11, 12, 13, 14, 15, 16, 17, 18]
if store_open is True if time is in store_hours:
elif store_hours is False:
I need help asap same question
Jason Anders
Treehouse Moderator 145,860 PointsJason Anders
Treehouse Moderator 145,860 Pointsuba chukwudire
When posting to the Community, please provide a descriptive title and then an explanation of the problem you are encountering, then any code that is relevant.
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Jason ~ Treehouse Community Moderator