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jamie Macdiarmid
2,048 PointsNeed help
Can someone show me how its done please?
I think it wouldn't be a bad idea if say after 20 mins of not knowing what to do a solution would be made available with perhaps some cliff notes on it.
What does anyone else think?
def even_odd(num):
if num == (num/2)
2 Answers
Tobias Helmrich
31,603 PointsHey Jamie,
to solve this challenge you have to use the modulo operator (%) which gives you the remainder of a division. If there is no remainder when you divide a number by two it's even and then you have to return True. Otherwise you have to return False as it's not even/odd:
Like this:
def even_odd(num):
if num % 2 == 0:
return True
else:
return False
And I think that's a good suggestion. However I imagine it a bit hard to implement as it's a bit hard to guess where exactly the student may have problems so I think a forum is a better way as it provides more individual feedback.
I hope that helps! :)
Melanie Villela
3,048 PointsHi Tobias I have a question. Could you put any value to replace (num) like could you type (x) as long you write the same (x) with the if statement?
Tobias Helmrich
31,603 PointsHey there Melanie,
yes, you can name the parameter however you want and x would work just as fine as num! :)
jamie Macdiarmid
2,048 Pointsjamie Macdiarmid
2,048 PointsThankyou so much Tobias. It was pretty simple after all. Doh!!
Tobias Helmrich
31,603 PointsTobias Helmrich
31,603 PointsNo problem, I'm glad I could help! :)