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Start your free trialkishor budhathoki
158 Pointsneed help
Now replace <YOUR NAME> in the console.printf expression with the firstName variable using the string formatter.
// I have setup a java.io.Console object for you named console
String firstName = "kishor";
console.printf("kishor can code in java");
consloe.printf("%s can code in java", firstname);
2 Answers
Sean M
7,344 PointsYou accidentally mistyped firstName. You just need to make sure to use camel case for referencing in Java. It should be:
console.printf("%s can code in java", firstName);
Hope that helped.
<noob />
17,062 PointsHi! you have a 2 typos in your code, instead of "console" you typed consloe:
consloe.printf("%s can code in java", firstname);
and instead of firstName, you typed "firstname", u dont refer to ur firstName var and because of that u cant get the name.
consloe.printf("%s can code in java", firstname);
the correct code look like this:
String firstName = "kishor";
console.printf("kishor can code in java");
console.printf("%s can code in java", firstName);
if this answer helped mark this answer as best answer
Farai Ted Mandoreba
21,518 Pointsthanks guys you are very helpful it helped
Farai Ted Mandoreba
21,518 PointsFarai Ted Mandoreba
21,518 Pointsthank you it helped