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Python Python Basics (2015) Letter Game App Even or Odd Loop

Suleiman Abdurozikov
Suleiman Abdurozikov
2,943 Points

need a help

please help me

even.py
Alright, last step but it's a big one.
Make a while loop that runs until start is falsey.
Inside the loop, use random.randint(1, 99) to get a random number between 1 and 99.
If that random number is even (use even_odd to find out), print "{} is even", putting the random number in the hole. Otherwise, print "{} is odd", again using the random number.
Finally, decrement start by 1.
I know it's a lot, but I know you can do it!



import random
start = 5
def even_odd(num):
    while True:
        try:
            if start == 0
        except ValueError:
            break
    while True:
        number0 = random.randint(1, 99)
        if random.randint(1,99) % 2 = 0:
            return("{} is even".format(number0))
        else:
            if random.randint(1, 99) % 2 != 0:
                return("{} is odd".format(number0))
         start -= 1       

1 Answer

Brian Jensen
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree seal-36
Brian Jensen
Treehouse Staff
import random
start = 5

def even_odd(num):
    return not num % 2

while start:
  num = random.randint(1, 99)
  if even_odd(num):
    print("{} is even".format(num))
  else:
    print("{} is odd".format(num))
  start = start - 1