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JavaScript JavaScript Functions Arrow Functions Testing for Number Arguments

Posted by Hina K.
Hina K.
4,806 Points

My solution (different from the tutorial). Does this work? I used the '&&' operator. 

const random = (lowNum, highNum) => {
    if (!isNaN(lowNum) && !isNaN(highNum)) {
        return Math.floor((Math.random() * (highNum - lowNum + 1) + lowNum));
    } else {
        console.log("Enter two numbers and try again.");
  }
}

** Call functions I used **

console.log(random(10, 30));
console.log(random(20, 40));
console.log(random('a', 40));
console.log(random(0, 2));

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

Inverting the logic to test for a good condition instead of a bad one is perfectly legitimate from a functional perspective, and a good example of how there's rarely just one solution when programming. Good job!   :+1: