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Start your free trialRicardo Lousada
7,487 PointsMy code works fine with my tests using spider and it's not working here
The code is:
def loopy(items): # Code goes here for i in range(len(items)): if items[i] == "a" and i == 0: continue print(items[i])
items = ['a','b',"a",2,3,4,5]
loopy(items)
def loopy(items):
# Code goes here
for i in range(len(items)):
if items[i] == "a" and i == 0:
continue
print(items[i])
2 Answers
Jennifer Nordell
Treehouse TeacherHi there! You're close here, but you're checking the incorrect thing. You're checking the entire item in the item list. Let's say for example that the first item in your items array had been 'apple'. The code challenge would want you to skip that one because that word starts with an 'a'. So instead of the item specifically being 'a' it needs to only start with an 'a'.
def loopy(items):
# Code goes here
for i in items:
if i[0] == 'a':
continue
print(i)
Keep in mind that you should not define an items array yourself. This will be supplied by Treehouse.
Here we set up our loopy function. For every i
in the items list if the first position inside that i
(index 0) is equal to "a" we will skip it. Otherwise, we print out i
. Hope this helps!
Ricardo Lousada
7,487 PointsThank you Jennifer it was very helpfull.