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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Robert Brasso
Robert Brasso
1,277 Points
Posted by Robert Brasso
Robert Brasso
1,277 Points

My code works but it won't let me move on. I've tried a bunch of variations that work, but it won't let me proceed.

why?

Name.java 
// I have setup a java.io.Console object for you named console
String firstName = "Nick";
console.printf (firstName);

1 Answer

Rob Bridges
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Rob Bridges
Full Stack JavaScript Techdegree Graduate 35,467 Points
Rob Bridges
.a{fill-rule:evenodd;}techdegree seal-36
Rob Bridges
Full Stack JavaScript Techdegree Graduate 35,467 Points

Hey Chris, Two things. The 1st and most simpelest is the string that they are looking for is "<Your name> can code in java!"

You're just printing off the variable without the code.

The other thing, that I think gets to the heart of the challenge is you need to actually pass in the variable as a placeholder at first.

It would look something like this.

console.printf("%s can code in Java!", firstName);

I'd go back and review the video a bit to see what the printf function can do for you.

Thanks, hope this helped.