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Start your free trialSebastian Salas
Courses Plus Student 2,839 PointsMy code return the right answer
why the following code is not right?
def squared(num):
try:
x = int(num)
print(int(num) * int(num))
except Exception:
print(len(num) * num)
squared(10)
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(num):
try:
x = int(num)
print(int(num) * int(num))
except Exception:
print(len(num) * num)
squared(10)
1 Answer
Codin - Codesmite
8,600 Pointsdef squared(num):
try:
int(num)
except:
return num * len(num)
else:
return int(num) ** 2
The challenge asks you to return the value not print it to the screen.
You also do not need to define
x = int(num)
as you do not use
x
anywhere in the scope,
int(num)
is suffecient to test if
num
can be converted to an integer.