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Start your free trialHermes Crespo
980 PointsMy code obviously shows that I declared the array variable as double so why am I getting the message that i need to....
... declare the array variable as double?? I coded: double[] lapTimes = new lapTimes[4];
double[] lapTimes = new lapTimes[4];
1 Answer
Joe Beltramo
Courses Plus Student 22,191 PointsYou are close, in declaring an array, you want to initialize it with the type, not the name of the variable itself. Since there is no way to explain without actually giving you the answer, welp, here it is:
double[] lapTimes = new double[4]; // Notice using the type `double` instead of lapTimes by the instantiation of length
Hermes Crespo
980 PointsHermes Crespo
980 PointsThanks! I did do something similar but had left a space as so: new double [4] ... thus, also got an error message. But now I know better thanks to you. Thanks again!