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Start your free trialAnastasia Khmelevskaya
1,775 PointsMultidimensional array assignment error - having correct output but assignment labeled as incorrect?
Assignment called to replace hard coded values with name and email values from contacts array. Can someone please explain what I'm doing wrong?
<?php
//edit this array
$contacts [] = [
'name' => 'Alena Holligan',
'email' => 'alena.holligan@teamtreehouse.com',
];
$contacts [] = [
'name' => 'Dave McFarland',
'email' => 'dave.mcfarland@teamtreehouse.com',
];
$contacts [] = [
'name' => 'Treasure Porth',
'email' => 'treasure.porth@teamtreehouse.com',
];
$contacts [] = [
'name' => 'Andrew Chalkley',
'email' => 'andrew.chalkley@teamtreehouse.com',
];
echo "<ul>\n";
//$contacts[0] will return 'Alena Holligan' in our simple array of names.
echo $contacts [0]['name'];
echo $contacts [0]['email'];
echo $contacts [1]['name'];
echo $contacts [1]['email'];
echo $contacts [2]['name'];
echo $contacts [2]['email'];
echo $contacts [3]['name'];
echo $contacts [3]['email'];
echo "</ul>\n";
?>
2 Answers
Jennifer Nordell
Treehouse TeacherHi there, Anastasia Khmelevskaya! The original output looked like this for Alena, for example:
echo "<li>$contacts[0]['name'] : $contacts[0]['email']</li>\n";
What you are printing out right now doesn't match this format nor are they encased in <li>
tags.
Here's an example of what it's expecting using only Alena:
echo "<li>" . $contacts[0]['name'] . " : " . $contacts[0]['email'] . "</li>\n";
You're going to need to do a bit of concatenation to make the string look exactly like what it originally was. Hope this helps!
Anastasia Khmelevskaya
1,775 PointsHi Jeniffer, thanks so much!