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PHP PHP Arrays and Control Structures PHP Arrays Multidimensional Arrays

Posted by Wouter Vermeersch
Wouter Vermeersch
6,913 Points

multi dimensional arrays -> validation bug?

Hello, my attached code just works fine, and spits out the correct data, unfortunately it does not validates as correct,.... hmmmmm .. help team treehouse?

index.php 
<?php
//edit this array
$contacts = array(array('name' => 'Alena Holligan'), array('name' => 'Dave McFarland'), array('name' => 'Treasure Porth'), array('name' =>'Andrew Chalkley'));

echo "<ul>\n";
//$contacts[0] will return 'Alena Holligan' in our simple array of names.
echo "<li>Alena Holligan : alena.holligan@teamtreehouse.com</li>\n";
echo "<li>Dave McFarland : dave.mcfarland@teamtreehouse.com</li>\n";
echo "<li>Treasure Porth : treasure.porth@teamtreehouse.com</li>\n";
echo "<li>Andrew Chalkley : andrew.chalkley@teamtreehouse.com</li>\n";
echo "</ul>\n";
Wouter Vermeersch
Wouter Vermeersch
6,913 Points

omg it just added the first step index.php file .. :/

this was my code at the last step:

<?php
//edit this array
$contacts = array(array('name' => 'Alena Holligan', 'email' => 'alena.holligan@teamtreehouse.com'), array('name' => 'Dave McFarland', 'email' => 'dave.mcfarland@teamtreehouse.com'), array('name' => 'Treasure Porth', 'email' => 'treasure.porth@teamtreehouse.com'), array('name' =>'Andrew Chalkley', 'email' => 'andrew.chalkley@teamtreehouse.com'));

echo "<ul>\n";
//$contacts[0] will return 'Alena Holligan' in our simple array of names.

/* Approach one does not pass*/
echo '<li>'.$contacts[0]["name"].' : '.$contacts[0]["email"].'</li>';
echo '<li>'.$contacts[1]["name"].' : '.$contacts[1]["email"].'</li>';
echo '<li>'.$contacts[2]["name"].' : '.$contacts[2]["email"].'</li>';
echo '<li>'.$contacts[3]["name"].' : '.$contacts[3]["email"].'</li>';
echo "</ul>\n";

/* Approach twoo does not pass neither*/
$i = 0;
echo "<ul>\n";
foreach($contacts)
{
  echo '<li>'.$contacts[$i]["name"].' : '.$contacts[$i]["email"].'</li>';
  $i++;
}
echo "</ul>\n";

1 Answer

Ryan S
Ryan S
27,276 Points
Ryan S
Ryan S
27,276 Points

Hi Wouter,

The key is in the error message. It says that you should not modify the output, however, you have taken out the newline characters ("\n") at the end of each list item. You will need to add those newlines back in, and don't forget that you will need to use double quotes rather than singles in order to interpret an escaped character in PHP.

Good luck.