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Start your free trialMichael Walker
45,428 PointsModifying the Code
Is there any easy way to modify the code so we don't have the common bug listing one song as songs as Craig pointed out in the video? Here's what I have, but I'm sure there is a much easier way to access the count. Any ideas?
if (songBook.getSongCount() == 1) { System.out.printf("There is %d song. %n", songBook.getSongCount()); } else { System.out.printf("There are %d songs. %n", songBook.getSongCount()); }
2 Answers
deckey
14,630 PointsHi Michael, your approach is fine, except some redundant code.
Since we already established that there is 1 song in the first condition, then there is no need to call the method again just for printing results, so:
if (songBook.getSongCount()== 1) {
System.out.println("There is 1 song. %n");
}
cheers
Michael Walker
45,428 Pointslol, I didn't even think of that. You get so used to calling methods all the time, it didn't even occur to me I didn't need a placeholder there. Thanks deckey!