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Start your free trialWilson Chan
5,886 PointsMissing return Statement
Anyone can help to solve this?? i have stuck here for a long time nw....i tried using eclipse to solve it but runs well ..
public class ConferenceRegistrationAssistant {
public int getLineFor(String lastName) {
/* If the last name is between A thru M send them to line 1
Otherwise send them to line 2 */
int line1 = 0,line2=0;
char getName = lastName.charAt(0);
if(getName>='A' && getName<='M'){
return ++line1;
}
else if(getName<='Z'&&getName>='N'){
return ++line2;
}
}
}
1 Answer
Steve Hunter
57,712 PointsHiya,
You're overcomplicating that. The test is mutually exclusive - lastName
begins with a letter. Letters are between A and Z; those are safe assumptions. The queue is divided after 'M' or when the initial letter < 'N'. There's no need to check if a letter is >= than to 'A'; they all are; similar to less than or equal to 'Z'. We're not catching typos here.
So you just need to see if the initial letter is less than N, if it is, set line to 1, else set lie to 2. Return the line number.
public int getLineFor(String lastName) {
/* If the last name is between A thru M send them to line 1
Otherwise send them to line 2 */
int line = 0;
if (lastName.charAt(0) < 'N') {
line = 1;
} else {
line = 2;
}
return line;
So, the function takes a surname and returns which line the person needs to stand in.
I hope that helps!
Steve.
Wilson Chan
5,886 PointsWilson Chan
5,886 PointsOh I See!!!! Thanks Steve!!
Steve Hunter
57,712 PointsSteve Hunter
57,712 PointsHaha! I know, it is one of those that leads people down the mega-complicated route very easily! There's only one test needed and the result of that splits into two lines.
Everything is simple when you know the answer! This one catches quite a few people out; which is good - it gets us all thinking.
Steve.
Wilson Chan
5,886 PointsWilson Chan
5,886 Pointsyeah!! i was thinking what went wrong...it is actually that simple...hahah still a long way for a rookie like me hahaha