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JavaScript JavaScript Basics (Retired) Working With Numbers The Random Challenge Solution

Posted by ravichandrakonda
ravichandrakonda
2,255 Points

Math.floor(math.random() * (A - B + 1))+B Gives you a no. btwn 10 to 25 including 10.

as per the video. it gives a number between 10 and 25 including 10. because when math.random() randomly gives 0.02, it becomes 0.02 * (25-10+1) which is 0.32 and when you apply floor, it becomes 0. so 0 + B gives you 10. but not a number between 10 and 25.

whereas, if you put the +1 outside, it gives a number between 10 and 25. ex: Math.floor(math.random() * (A - B)) + 1+ B.

Please correct me If I'm wrong.!! Expecting a quicker response.

Thanks, Ravi.

Damjan Bozinovski
Damjan Bozinovski
9,916 Points

My guess is that math.random returns only one decimal, for example 0.1, 0.2 etc. Then it makes sense. I don't think that it can return as you wrote 0.32. When you do that math the way I said it, it's gonna be a number between 10 and 25 in this case.

Hope it helps :D

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

FYI: Regarding precision, here's a typical sample value from Math.random() :point_right: 0.3425137594155696

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

This is the formula for an inclusive random number range. The reason that 1 is added to A - B is so that the range will be large enough to make it possible for the top number to be selected. If you add one to the value after multiplying, you're just raising (and excluding) the minimum.

So, for example if A = 25 and B = 10:
"Math.floor(Math.random() * (A - B + 1)) + B" will produce a number from 10 to 25, but
"Math.floor(Math.random() * (A - B)) + 1 + B" will produce a number from 11 to 25.

That second formula is halfway to being the one for an exclusive range, which is:
"Math.floor(Math.random() * (A - B - 1)) + 1 + B" .