If I am reading that error output correctly it appears that you are trying to use a string literal somewhere in which your program is expecting an int. However I concur with Josh Keenan that posting your code might be really useful to help with the debugging of it.

i ran into the same problem and still dont know how to fix it

I have the same problen and I don't know how to fix it

ticket_price = 10 ticket_remaining = 100

while ticket_remaining >= 1: print("There are {} tickets remaining.".format(ticket_remaining)) name = input("What is your name? ") number_tickets = input ("How many tickets do you want, {}? ".format(name)) try: number_tickets = int(number_tickets) if number_tickets > ticket_remaining: raise ValueError ("There is only {} tickets remaining.".format(ticket_remaining)) except ValueError as err: print("Aconteceu um erro. {}. Por favor, tente novamente!".format(err)) else: total_price = (number_tickets) * (ticket_price) print("The total price will be $",total_price,".") ask = input ("Do you wnant to proceed? Y/N ") if ask.lower() == "y": print ("SOLD!") ticket_remaining -= int(number_tickets) else: print("No problem! Thanks {}.".format(name)) print("there is no more tickets available")

I'll post the code on behalf of the others as I'm also experiencing this problem. Following the challenge exactly as Craig has, this (invalid literal for int() with base 10: 'blue') error only began to happen after using the raise ValueError within the try.

So before this, if you entered a non numerical answer of how many tickets you wanted (i.e. Blue), it would print the "we ran into an issue" error and loop back. Now after adding the ValueError for requesting tickets above the number remaining, it breaks the flow of presenting the correct error message.

I'm pretty certain it's because it's now trying to print the error with {} variable formatted to {err}. However, that {err} variable hasn't been set because it did not pass through the if num_tickets > tickets remaining statement as it was a non numerical value that was entered (blue).

The order I believe it's now going in:

1. It sets num_tickets to blue (based on user input)
2. Goes through the try statement and attempts to convert Blue to an int which is not possible.
3. Skips the if statement because a ValueError has been raised and tries to print the ValueError defined as {err}.
4. Can't print the {err} part of the message because it did not go through the if statement which sets the ValueError message hence why it's still printing the manually written text within the print() statement.

I am pretty new to Python but familiar with reading other languages, so although I can see what's happening, I have no idea how to fix it or do it in the correct order.

TICKET_PRICE = 10

tickets_remaining = 100  


while tickets_remaining >= 1:
    print("There are {} tickets remaining".format(tickets_remaining))
    name = input("What is your name?  ")
    # Expect a ValueError to happen and handle it appropriately... remember to test it out!
    num_tickets = input("How many tickets would you like, {}?  ".format(name))
    try:
        num_tickets = int(num_tickets)
        # Raise a ValueError if the request is for more tickets than are available.
        if num_tickets > tickets_remaining:
            raise ValueError ("There are only {} tickets remaining".format(tickets_remaining))
    except ValueError as err:
        #include the error text in the output.
        print("Oh no, we ran into an issue. {}.  Please try again!".format(err))
    else:
        price = num_tickets * TICKET_PRICE
        print("The price is: £{}".format(price))
        proceed_YN = input("Do you want to proceed?  Y/N  ")
        if proceed_YN.lower() == "y":
            # TODO: Gather credit card information and process it.
            print("SOLD!")
            tickets_remaining -= num_tickets
        else:
            print("Thank you anyways, {}".format(name))
print("Tickets are sold out!")    

when I enter a number larger than 100, I am getting this error while trying to run the same code. invalid literal for int() with base 10:

Here is what my code looks like. why am I getting the above message?

SERVICE_CHARGE = 2 TICKET_PRICE = 10

tickets_remaining = 100

create the calculate price function. It takes number of tickets and returns

num_tickets * TICKET_PRICE

def calculate_price(number_of_tickets): # create a new constant for the 2 dollar service charge
#Add the service charge to our result return (number_of_tickets * TICKET_PRICE) + SERVICE_CHARGE while tickets_remaining >= 1: print("There are {} tickets remaining.".format(tickets_remaining)) name = input("What is your name?" ) num_tickets = input("How many tickets would you like, {}? ".format(name)) # expect a ValueError to happen and handle it appropriately...remember to test it out. try: num_tickets = int(num_tickets) #Raise ValueError if the request is for more tickets than are available if num_tickets > tickets_remaining: raise ValueError("There are only {} tickets remaining".format(tickets_remaining)) except ValueError as err: #Include the error text in the output print("Oh no, we ran into an issue. {}. Please try again".format(err)) else: amount_due = calculate_price(num_tickets) print("The total due is ${}".format(amount_due)) should_proceed = input("Do you want to proceed Y/N ") if should_proceed.lower()=="y": #TODO: gather credit card information and process it. print("SOLD!") tickets_remaining -= num_tickets else: #Thank them by name print("Thank you anyways, {}!".format(name)) print ("Sorry the tickets are all sold out!!:(")