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Julio Lugo
588 Pointsloopy challenge
please help me with this challenge task.. I spent hours already without luck. I cant pass to the next exercise
#Same idea as the last one. My loopy function needs to skip an item this time, though.
#Loop through each item in items again. If the character at index 0 of the current item is the letter "a",
#continue to the next one. Otherwise, print out the current member.
#Example: ["abc", "xyz"] will just print "xyz".
def loopy(items):
# Code goes here
for item in items :
if item.index(0) == "a" :
continue
else:
print(letter)
1 Answer
Jamie Marsay
8,320 PointsHi Julio!
You're very close to the solution, but there's a few errors in your code!
Firstly:
if item.index(0) == "a" :
should be:
if item [0] == "a":
The "[0]" references the index of the character, so that will correct that error
Secondly: The "else" statement of your code is correct, but you're telling it to print the "letter" variable, which is not actually used in your "for" loop, so Python has no idea what it is that you're wanting to print.
Your "for" loop is looping through the items and assigning them the variable "item".
for item in items:
By changing
print(letter)
to
print(item)
Python will know which "item" it is that you want printing.
Alternatively, you could change:
for item in items:
to:
for letter in items:
I hope this helps!
Regards, James.