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Start your free trialJesse Fister
11,968 Pointsloops in ruby
I don't quite understand the question... Using the loop construct, add the current value of number to the numbers array. Inside of the loop, add 1 to the number variable. Use the break keyword to exit the loop once the numbers array has 3 items.
I've started my code with:
loop do number + 1 break end
If someone could explain this question that would be great!
1 Answer
Lee Geertsen
Java Web Development Techdegree Student 16,749 PointsSo you first start your loop. Then you put 'number' in the 'numbers' array using the 'push()' method. Then you check if your array has 3 objects in it using the 'if' conditional and the 'length' method on the 'numbers' array. If your array contains 3 objects you break. If not so you increment the 'number' variable by 1
# write your loop here
loop do
numbers.push(number)
if numbers.length() == 3
break
end
number += 1
end