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Start your free trialGrace Baecher
578 PointsLoop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to th
Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one.
def loopy(items):
if item in items:
if item == ["a"]:
continue
print(item)
# Code goes here
1 Answer
Valeshan Naidoo
27,008 Pointsdef loopy(items):
if item in items: <-- use a for loop since we are looping through each of the item in the items list
if item == ["a"]: <-- item should have the index 0, so item[0], we are searching for the first letter of each item,
continue remove the [] around "a" since it's not part of anything, it's just a string.
print(item) <-- this shouldn't be indented in the if statement, you can put that in an else statement.
so in the end it should look like this:
def loopy(items):
for item in items:
if item[0] == "a":
continue
else:
print(item)
Valeshan Naidoo
27,008 PointsValeshan Naidoo
27,008 Pointsyou can also just forgo the "else", and just do