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Start your free trialIvan Ilievs
860 PointsLooks like you threw a different exception instead of the IllegalArgumentException. java.lang.NullPointerException.
What is wrong here ?
import java.io.Console;
public class TeacherAssistant {
public static String validatedFieldName(String fieldName) {
// These things should be verified:
// 1. Member fields must start with an 'm'
// 2. The second letter in the field name must be uppercased to ensure camel-casing
// NOTE: To check if something is not equal use the != symbol. eg: 3 != 4
String mFieldName;
Console console = System.console();
mFieldName = console.readLine();
if(fieldName != mFieldName){
throw new IllegalArgumentException("Valuse that you passed doesn't validate the field name");
}
return fieldName;
}
}
1 Answer
Daniel Hartin
18,106 PointsHi Ivan
It looks like you're not checking the input correctly, you need to follow the directions given in order to validate the passed in String. The way I did it is posted below however i'm not sure if you have covered these methods or not.
In case you want to figure this out for yourself my hint to you would be "split the String into an array first in order to separate the individual characters, then check the indexes of the characters to validate".
public class TeacherAssistant {
public static String validatedFieldName(String fieldName) {
// These things should be verified:
// 1. Member fields must start with an 'm'
// 2. The second letter in the field name must be uppercased to ensure camel-casing
// NOTE: To check if something is not equal use the != symbol. eg: 3 != 4
char[] fieldArray = fieldName.toCharArray();
if(fieldArray[0] == 'm' && Character.isUpperCase(fieldArray[1])){
return fieldName;
}else{
throw new IllegalArgumentException();
}
}
}
Hope this helps
Daniel
Mikkel Frederiksen
5,539 PointsMikkel Frederiksen
5,539 PointsThis might be more appropriate at this stage of the course.