Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialGilang Ilhami
12,045 PointsLetter game
i'm not sure what's wrong her
when the answer given is 'banana' or 'apple' it doesn't let me win and quit the game
```python import random
make a list of words
words = [ 'apple', 'banana', 'orange', 'strawberry', 'lime', 'grapefruit', 'lemon', 'kumpquat', 'blueberry', 'melon', ]
while True: start = input("Press enter or return, or press Q to quit ") if start.lower() == 'q': break
# pick a random word
secret_word = random.choice(words)
good_guesses = []
bad_guesses = []
while len(bad_guesses) < 7 and len(good_guesses) != len(list(secret_word)):
# draw spaces, guesses letter, and strikes
for letter in secret_word:
if letter in good_guesses:
print(letter, end='')
else:
print ('_', end='')
print ('')
print ("Strikes: {}/7".format(len(bad_guesses)))
print ('')
# take guess
guess = input("Take a guess:").lower()
if len(guess) != 1:
print ("You should answer one letter at a time!")
continue
elif guess in bad_guesses or guess in good_guesses:
print ("You already use that letter")
continue
elif not guess.isalpha():
print ("You can only type letters!")
continue
if guess in secret_word:
good_guesses.append(guess)
if len(good_guesses) == len(list(secret_word)):
print ("You win! The word was {}!".format(secret_word))
break
else:
bad_guesses.append(guess)
else:
print("Sorry you lose... the word was {}".format(secret_word))
1 Answer
Steven Parker
231,236 PointsYou need a different strategy for finding a win.
In the code above, you check the number of correct guesses against the length of the word to determine a win. That will work for words where every letter is different, but for words with repeated letters like 'banana' or 'apple' a win will occur while the number of good guesses is less than the size of the word.
You need a different checking strategy. What if you compared the size of good_guesses against only the number of unique letters, or checked if each letter of the word was in good_guesses?