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hashir suleiman
190 Points.join() .format()
Alright, let's finish making our menu. Combine the sundaes list into a new variable named display_menu, where each item in the list is rejoined together by a comma and a space (", "). Then reassign the menu variable to use the existing variable and .format() to replace the placeholder with the new string in display_menu. If you're really brave, you can even accomplish this all on the same line where menu is currently being set.
available = "banana split;hot fudge;cherry;malted;black and white"
sundaes = available.split(";")
menu = "Our available flavors are : {}"
display_menu = "Our available flavors are : {}".join(", ".format(display_menu))
hashir suleiman
190 Pointssorry ammar its still says error. But anyways thanks
2 Answers
james south
Front End Web Development Techdegree Graduate 33,271 Pointsyou are calling join backwards. the string you call join on is the delimiter, so it will go between each element in the collection that you supply to join as the argument. so if i call 'TTT'.join('abc') the return will be 'aTTTbTTTc'.
Ammar Fatihallah
7,417 PointsHave you tried making sundaes a list ? Like this maybe : list(available.split(";"))
Ammar Fatihallah
7,417 PointsAmmar Fatihallah
7,417 PointsVery close Hashir, very close. Your code is all correct until the last part, the .format(display_menu). It's wrong because, in the format, you were supposed to include the list of flavors; but you included a string that doesn't have a list. Your code should've looked something like this: .format(sundaes)