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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

java.util.MissingFormatArgumentException: Format specifier '%s' ()

i keep getting this error, even thou i put the right selector

Name.java
// I have setup a java.io.Console object for you named console
String firstName = "Andreea";
console.printf("%s can code in Java!, firstName");

1 Answer

Hello, when using the formatted print method (printf) the argument should be passed after closing off the string and after a comma. The compiler is saying okay I have this string and the format specifier but nothing to replace it with. So, simply moving the firstName variable name after the ending double quote and after a comma, your code will work