Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialIoan Popaluca
654 Pointsjava.util.MissingFormatArgumentException: Format specifier '%s' ()
i keep getting this error, even thou i put the right selector
// I have setup a java.io.Console object for you named console
String firstName = "Andreea";
console.printf("%s can code in Java!, firstName");
1 Answer
Bradley Williams
4,545 PointsHello, when using the formatted print method (printf) the argument should be passed after closing off the string and after a comma. The compiler is saying okay I have this string and the format specifier but nothing to replace it with. So, simply moving the firstName variable name after the ending double quote and after a comma, your code will work