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Start your free trialAYMERIC FIGEROU
3,748 Pointsjava.util.MissingFormatArgumentException: Format specifier '%s' ()
Hello TreeHouse Com,
Quite don't get it why there is a message error. My variable has been declared, following by the string formatter %s. It sounds good. or?
// I have setup a java.io.Console object for you named console
String firstName="Jaean";
console.printf("%s");
console.printf(" can code in Java");
2 Answers
Christopher Augg
21,223 PointsAymeric,
You should only use one console.printf(). On task 3/3 you are supposed to just alter it to use %s. When formatting a string that includes a variable we do the following:
String titleOfMovie = "The Shawshank Redemption";
console.printf("I really enjoyed watching %s", titleOfMovie);
So how would you do it for the challenge?
Hope this helps.
Regards,
Chris
AYMERIC FIGEROU
3,748 PointsIt does indeed. I didn't understand i had to respecify it. If i can say so.
Thanks you