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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Posted by ryan backert
ryan backert
75 Points

its to difficult

43t45

Name.java 
// I have setup a java.io.Console object for you named ="ryan can code in java";
String firstName ="%s";
console.printf ("%s code in java /n,firstName);

1 Answer

daniel104729
daniel104729
7,176 Points
daniel104729
daniel104729
7,176 Points

You may want to change firstName to a name like Zoe or Ryan. The issue I am guessing is that you forgot a double quote " after /n and before ,firstName. Also, you probably want \n and not /n. \n is newline and /n is nothing special

You may be discouraging help by saying you think the problem is too difficult

Ole Vølund Skov Mortensen
Ole Vølund Skov Mortensen
27,841 Points
Ole Vølund Skov Mortensen
Ole Vølund Skov Mortensen
27,841 Points

I'll merely add: Remember; it should be referenced to the instance started. if it's within the same class(like yours) it's "this.firstName" other than that, the above is a bare minimum. ' " ' is missing and \n. all great advise!