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Start your free trialBarak TheProgrammer
1,773 Pointsit tells me to do $array[#][STRING]
it tells me to do $array[#][STRING], thats what im doing and it just dont accept it.
<?php
//edit this array
$contacts = array(
array('name' => 'Alena Holligan', 'email' => 'alena.holligan@teamtreehouse.com'),
array('name' => 'Dave McFarland', 'email' => 'dave.mcfarland@teamtreehouse.com'),
array('name' => 'Treasure Porth', 'email' => 'treasure.porth@teamtreehouse.com'),
array('name' => 'Andrew Chalkley', 'email' => 'andrew.chalkley@teamtreehouse.com')
);
//$contacts[0] will return 'Alena Holligan' in our simple array of names.
for($i=0; $i<4; $i++){
echo ($i+1) . " ";
echo "name: " . $contacts[$i]['name'] . "<br />\n";
echo "email: " . $contacts[$i]['email'] . "<br />\n";
}
?>
2 Answers
Antonio De Rose
20,885 Points <?php
$contacts = array('Alena Holligan', 'Dave McFarland', 'Treasure Porth', 'Andrew Chalkley');
$contacts = array (
array ( 'name' => 'Alena Holligan', 'email' => 'alena.holligan@teamtreehouse.com'),
array ( 'name' => 'Dave McFarland','email' => 'dave.mcfarland@teamtreehouse.com'),
array ( 'name' => 'Treasure Porth','email' => 'treasure.porth@teamtreehouse.com'),
array ( 'name' => 'Andrew Chalkley','email' => 'andrew.chalkley@teamtreehouse.com')
);
echo "<ul>\n";
echo "<li>" . $contacts[0]['name'], ' : ' . $contacts[0]['email'] . "</li>\n";
echo "<li>" . $contacts[1]['name'], ' : ' . $contacts[1]['email'] . "</li>\n";
echo "<li>" . $contacts[2]['name'], ' : ' . $contacts[2]['email'] . "</li>\n";
echo "<li>" . $contacts[3]['name'], ' : ' . $contacts[3]['email'] . "</li>\n";
echo "</ul>\n";
?>
Barak TheProgrammer
1,773 PointsTHANKS!