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Python Python Basics (2015) Python Data Types Specific Index value

Is this bugged?

I'm told to define varl as a string or list.
varl = "abcdet"
when I hit check I get a NameError?

index.py
varl = "abcdet"

3 Answers

Vittorio Somaschini
Vittorio Somaschini
33,371 Points

Hello Michael.

Please note that you have defined the varl variable (with a trailing "l"), the code challenge is asking for a var1 variable (last character should then be the number one).

;) Vitto

Ryan S
Ryan S
27,276 Points

Hi Michael,

I think it is the font that is confusing, but it should be var1 (var-one), not varl (var-L).

Good luck.

haha wow, that was embarrassing, thanks again for your time and pointing that out. Worked a double, my attention to detail is lacking at this point!