Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Posted by Alex Potham
Alex Potham
860 Points

is this a bug because i am doing it exactly right and it wont recognise my name as a string variable.

Challenge Task 1 of 3

Define a string variable named firstName that stores your name. Set the value to your name.

Name.java 
// I have setup a java.io.Console object for you named console
String FirstName = "Alex" ;

3 Answers

anil rahman
anil rahman
7,786 Points
anil rahman
anil rahman
7,786 Points

This is not a bug, it's your variable naming standards:

meaning you have not complied with the camelCase standard of naming your variable.

String firstName = "Alex" ;
Alex Potham
Alex Potham
860 Points
Alex Potham
Alex Potham
860 Points

thanks for your help anil but why is the "f" in "firstName" got to be in lower case and how will i know when to use captial letters?

anil rahman
anil rahman
7,786 Points
anil rahman
anil rahman
7,786 Points

It is the variable naming convention. This is called camelCase.

All variables you create should start with a lowercase character and any word after that should have the first letter capitalised.

Example:

String firstName //first letter is lower case and next word has first letter capitalised
String myNameIsAlex //Every other word is capitalised at the first character