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Python Dates and Times in Python (2014) Dates and Times Timedelta Minute

Posted by Trace Harris
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Trace Harris
Python Web Development Techdegree Graduate 22,065 Points

Is there an issue with my logic

So my understanding is that I am supposed to get the total seconds for each, then subtract the 1st from the second then floor divide by 60 and return that value, or should I subtract datetime1 from datetime2 then get the timedelta.total_seconds() and divide by 60 and return the resulting value?

minutes.py 
import datetime

def minutes(dt_one, dt_two):
    seconds_one = dt_one.timedelta.total_seconds() 
    seconds_two = dt_two.timedelta.total_seconds()
    total_sec =seconds_one - seconds_two 
    t1 = total_sec // 60
    return t1

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

You're on the right track with your alternate suggestion. You get the total seconds from the difference between the times, which will be a timedelta. Here's a few other hints:

  • you'll need to subtract the times first
  • the function "total_seconds" is used on a timedelta but does not have that word in it's name
  • the challenge wants "the number of minutes, rounded", not truncated ("floor"ed)