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JavaScript Object-Oriented JavaScript Object Basics Filling Out the Play Method

Posted by Zak Mosbacher
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Zak Mosbacher
Full Stack JavaScript Techdegree Graduate 16,080 Points

Is there a bug or something because i see no error in this :(

Why isnt this working, thanks for the help

object.js 
const player1 = {
    name: 'Ashley',
    color: 'purple',
    isTurn: true,
    play: function(){
        if(this.isTurn){
        let string = this[0] +' is now playing!;
        return string;
        }else{

        }
    }
}

1 Answer

Jason Anders
MOD
Jason Anders
Treehouse Moderator 145,860 Points
Jason Anders
Jason Anders
Treehouse Moderator 145,860 Points

Hey Zak,

You're really close. There are just a couple of things.

  • First, there is a missing closing quote for your string.
  • Second, the instruction state to "return a string equal to the value of the name property", but for some reason you have an integer being passed into the bracket notation. I think you're trying to use an index, but the actual key name needs to be used.
    Instead of this[0], you need this["name"].

Also, just a quick tip for DRY code:
Instead of declaring a new variable and storing the concatenated string, then returning the variable. You can just return the string being concatenated.

let nameOfString = variable["keyName"] + " is going to print out a line.";
return nameOfString;

The DRY way would be: 

return variable["keyName"] + " is going to print out a line.";

Both will result in identical output.

Anyway, hope that helps.
Nice work!! :) :dizzy: