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Michael Cafin
iOS Development Techdegree Student 1,221 PointsIs editor evaluating correctly. Please, advise
I think I have the correct solution, but the editor states that I have to double check my Fizz logic. Anyone?
func fizzBuzz(n: Int) -> String {
for i in 1...100 {
if (i % 3 == 0) && (i % 5 == 0) {
print("FizzBuzz")
} else if (i % 3 == 0) {
print("Fizz")
} else if (i % 5 == 0) {
print("Buzz")
} else {
print(i)
}
}
return "\(n)"
}
2 Answers
miikis
44,957 PointsHi Michael,
Essentially, your logic is fine; your if-else statements will get the job done on their own. But, our domain, in this case, is the one that the Challenge provides. And according to the challenge, the provided function takes an integer and your only job is to check if that integer is fizz, buzz or fizzbuzz and return a string accordingly.
The reason your code is not passing is that you're not doing any of these things: instead of returning strings you're printing stuff; instead of dealing only with the n argument that is passed into the function, you're creating your own range (1..100) and your own variable (i).
Fix those things and you'll pass that Challenge :)
Michael Cafin
iOS Development Techdegree Student 1,221 PointsHi Mikis, thank you for your response it is much appreciated. I will go ahead and start working on the feedback you provided me.
If I may ask - this particular challenge came with a video providing one possible answer. At first the solution to this challenge did not make sense to me because it did not match the assignment entirely, but moreover, when entering the code into the editor it did not approve the solution.
So, as you understand, I am a little confused because at first I had a switch statement turning on "n".
Could you please provide me with your thoughts on this situation. Thanks!