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Start your free trialSeth Estevis
441 PointsInvalid Syntax for an Exception, Please Help
I am getting a SyntaxError for line two where I am trying to create an exception. I want to create this exception because a user might enter "two" instead of "2" which breaks my program. Please advise on why I am getting this error. Thank you!
number=int(input("Please pick a number. "))
except ValueError:
print("Please pick an integer.")
if number < 100:
print("{} is less than 100!".format(number))
if number > 100:
print("{} is greater than 100!".format(number))
if number == 100:
print("{} equals 100!".format(number))
elif number == 200:
print("{} is the magic number!".format(number))
1 Answer
Steven Parker
231,269 PointsIf you want to catch errors, you need a "try" block before your "except". Take a look at the examples on the documentation pages that cover handling exceptions.
Seth Estevis
441 PointsSeth Estevis
441 PointsThank you for your advise! I found it very helpful reading the documents.