Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialahmed alfatih
Courses Plus Student 251 Pointsint numberOfPeople = 3; if (numberOfPeople < 4) { printf("Your table is ready"/n) ; } System.exit(0);
what is wrong with this code
int numberOfPeople = 3;
if (numberOfPeople < 4)
{
printf("Your table is ready"/n) ;
}
System.exit(0);
1 Answer
Stone Preston
42,016 Pointsyou need to use console.printf, not just printf. also the newline escape sequence is \n, not /n, and it belongs inside the string (between the " "):
int numberOfPeople = 3;
if (numberOfPeople < 4)
{
console.printf("Your table is ready\n") ;
}
System.exit(0);