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Java Hibernate Basics Getting Started with Hibernate Using the Builder Pattern

Posted by MUZ140721 Bothwell Nhidza
MUZ140721 Bothwell Nhidza
6,967 Points

In Application.java, replace the call to the Connection constructor with code that leverages the ConnectionBuilder

Am not sure what is wrong with my code.

com/teamtreehouse/builder/Connection.java 
package com.teamtreehouse.builder;

public class Connection {
  private String jdbcVendor;
  private String dbName;
  private String username;
  private String password;

  public Connection(String jdbcVendor, String dbName, String username, String password) {
    this.jdbcVendor = jdbcVendor;
    this.dbName = dbName;
    this.username = username;
    this.password = password;
  }

  public Connection(ConnectionBuilder builder) {
    this.jdbcVendor = builder.jdbcVendor;
    this.dbName = builder.dbName;
    this.username = builder.username;
    this.password = builder.password;
  }

  public static class ConnectionBuilder{
    private String jdbcVendor;
    private String dbName;
    private String username;
    private String password;

    public ConnectionBuilder(){}

    public ConnectionBuilder withJdbcVendor(String jdbcVendor) {
      this.jdbcVendor = jdbcVendor;
      return this;
    }

    public ConnectionBuilder withDb(String dbName) {
      this.dbName = dbName;
      return this;
    }

    public ConnectionBuilder withUser(String username, String password) {
      this.username = username;
      this.password = password;
      return this;
    }

    public Connection build() {
      return new Connection(this);
    }
  }
}
Application.java 
import com.teamtreehouse.builder.Connection;
import com.teamtreehouse.builder.Connection.ConnectionBuilder;

public class Application {
  public static void main(String[] args) {  
    Connection c = new Connection.ConnectionBuilder()
          .withJdbcVendor("sqlite")   
          .withDb("languages")
          .withUser("th_user", "mysuperlongpassword")
                .build();
      }
}