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Start your free trialkoltton fox
2,576 PointsIm stuck. trying to display flavors
didn't see an answer to this in community
<?php
$flavors = array();
$flavors[] = array("name" => "Cookie Dough", "in_stock" => true);
$flavors[] = array("name" => "Vanilla", "in_stock" => false);
$flavors[] = array("name" => "Avocado Chocolate", "in_stock" => false);
$flavors[] = array("name" => "Bacon Me Crazy", "in_stock" => true);
$flavors[] = array("name" => "Strawberry", "in_stock" => false);
//add your code below this line
foreach ($flavors) {
echo ['name'];
}
?>
1 Answer
calp
10,317 PointsYou're missing some little details on your loop. Here is the code I created when having a go at the challenge
<?php
$flavors = array();
$flavors[] = array("name" => "Cookie Dough", "in_stock" => true);
$flavors[] = array("name" => "Vanilla", "in_stock" => false);
$flavors[] = array("name" => "Avocado Chocolate", "in_stock" => false);
$flavors[] = array("name" => "Bacon Me Crazy", "in_stock" => true);
$flavors[] = array("name" => "Strawberry", "in_stock" => false);
//add your code below this line
foreach ($flavors as $flavor) {
if($flavor['in_stock']) {
echo $flavor['name'];
}
}
?>
koltton fox
2,576 Pointskoltton fox
2,576 Pointsthank you!