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Start your free trialJuan Losauro
783 PointsI'm stuck,
As you may see, I'm declaring a String variable and naming it "Juan" but as I print it, the exercise fails.
// I have setup a java.io.Console object for you named console
String fistName = "Juan";
console.printf(fistName + "can code in Java!");
2 Answers
Mohammed AlShaiban
6,455 PointsThe problem here is in your print statement, you need to add %s for the string to be printed.
console.printf("%s can code in Java!", firstName);
If you were using println instead of printf then your print statement would be correct.
Juan Losauro
783 PointsI've already noticed it! Thanks for the help mate!
Juan Losauro
783 PointsJuan Losauro
783 PointsOh wait I wrote fistName, sorry