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Python Python Basics (2015) Number Game App Squared

Jonathan Camacho
Jonathan Camacho
1,504 Points

I'm so exhausted from getting help. But I still cant comprehend what is wrong with this code.

It says that squared did not return the correct answer.

squared.py
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(arg):
    try:
        if int(arg) is True:
            return arg ** 2
    except ValueError:
        return arg * len(arg)

1 Answer

Rich Zimmerman
Rich Zimmerman
24,063 Points

In your If statement:

if int(arg):  # would return True, so you don't need the 'is True'

and then you just need to convert the arg to an int in that statement as well.

return int(arg) ** 2