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Start your free trialangel juarez
15,886 PointsI'm having problems with the normalizeDiscountCode, I don't know how to make it so it accepts $ and letters.
I believe that was able to make the method to check for letters but I don't know how to make the exception for the $. Any help will be appreciated.
public class Order {
private String itemName;
private int priceInCents;
private String discountCode;
public Order(String itemName, int priceInCents) {
this.itemName = itemName;
this.priceInCents = priceInCents;
}
public String getItemName() {
return itemName;
}
public int getPriceInCents() {
return priceInCents;
}
public String getDiscountCode() {
return discountCode;
}
private String normalizeDiscountCode(String discountCode){
for(char letter : discountCode.toCharArray()){
if(! Character.isLetter(letter)){
throw new IllegalArgumentException("Invalid discount code");
}
}
discountCode = discountCode.toUpperCase();
return discountCode;
}
public void applyDiscountCode(String discountCode) {
this.discountCode = normalizeDiscountCode(discountCode);
}
}
public class Example {
public static void main(String[] args) {
// This is here just for example use cases.
Order order = new Order(
"Yoda PEZ Dispenser",
600);
// These are valid. They are letters and the $ character only
order.applyDiscountCode("abc");
order.getDiscountCode(); // ABC
order.applyDiscountCode("$ale");
order.getDiscountCode(); // $ALE
try {
// This will throw an exception because it contains numbers
order.applyDiscountCode("ABC123");
} catch (IllegalArgumentException iae) {
System.out.println(iae.getMessage()); // Prints "Invalid discount code"
}
try {
// This will throw as well, because it contains a symbol.
order.applyDiscountCode("w@w");
}catch (IllegalArgumentException iae) {
System.out.println(iae.getMessage()); // Prints "Invalid discount code"
}
}
}
1 Answer
andren
28,558 PointsThe answer is simpler than you probably think it will be. Your solution is almost complete, you just need to add a single extra condition to your existing if statement. You are currently checking if the character is not a letter, if you also check that it is not equal to $ using the AND (&&) operator like this:
!Character.isLetter(letter) && letter != '$'
Then your if statement will work as intended, it will only run (and therefore throw the exception) if the character is not a letter and it is not the $ symbol. If the character is a letter, or is the $ symbol then it will not run.
angel juarez
15,886 Pointsangel juarez
15,886 PointsThank you