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Python Python Basics (2015) Letter Game App Even or Odd Loop

Balazs Bodor
Balazs Bodor
905 Points
Posted by Balazs Bodor
Balazs Bodor
905 Points

Im having difficulties seeing my syntax error

So, as I gather from this challenge, everything should be inside my While loop. But I'm having difficulties understanding where I'm going wrong. Should I start the while loop with random.randint(1, 99)? Am I formating the "print" statement wrong?

Also, I "decremented start by 1". I guess they mean that one should just adjust 5 to 4 in the "Start" statement, but what does that do?

Im stuck.

Thanks in advance

even.py 
import random
start = 4

while True:
    def even_odd(num):
        num = even_odd(random.randint(1, 99))
            if num % 2 == 0:
            print("{} is even".format(even_odd))
        else:
            print("{} is odd".format(even_odd))
            break
              # If % 2 is 0, the number is even.
              # Since 0 is falsey, we have to invert it with not.
karthikeyan s
karthikeyan s
105 Points

The reason for error is due to indentation at "break statement" and also you failed to call the function

1 Answer

karthikeyan s
karthikeyan s
105 Points
karthikeyan s
karthikeyan s
105 Points

import random start = 5

def even_odd(num): # If % 2 is 0, the number is even. # Since 0 is falsey, we have to invert it with not. return not num % 2 while start: rand = random.randint(1,99) if even_odd(rand): print("{} is even".format(rand)); else: print("{} is odd".format(rand)); start-=1;