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Start your free trialtylerduprey
Full Stack JavaScript Techdegree Student 25,399 PointsI'm getting the right result in the "result" tab but when I click "Check Work" It's not letting me pass.
I'm not sure what I'm doing wrong here. I'm clearly getting the desired outcome. If you click on the "results" tab it shows each name and email being dynamically updated. So, what's the problem?
<?php
//edit this array
$contacts = array(
$Alena = array('name' => 'Alena Holligan','email' => 'alena.holligan@teamtreehouse.com'),
$Dave = array('name' => 'Dave McFarland','email' => 'dave.mcfarland@teamtreehouse.com'),
$Treasure = array('name' => 'Treasure Porth','email' => 'treasure.porth@teamtreehouse.com'),
$Andrew = array('name' => 'Andrew Chalkley','email' => 'andrew.chalkley@teamtreehouse.com'),
);
echo "<ul>\n";
//$contacts[0] will return 'Alena Holligan' in our simple array of names.
echo "<li>" . $contacts[0]['name'] . " : " . $contacts[0]['email'] . "</li>\n";
echo "<li>" . $contacts[1]['name'] . " : " . $contacts[1]['email'] . "</li>\n";
echo "<li>" . $contacts[2]['name'] . " : " . $contacts[2]['email'] . "</li>\n";
echo "<li>" . $contacts[3]['name'] . " : " . $contacts[3]['email'] . "</li>\n";
echo "</ul>\n";
1 Answer
Mike Henry
Courses Plus Student 5,373 PointsHi tylerduprey, This is the answer that worked for me. <?php //edit this array $contacts = array( array('name'=>'Alena Holligan', 'email'=> 'alena.holligan@teamtreehouse.com'), array('name'=>'Dave McFarland', 'email'=> 'dave.mcfarland@teamtreehouse.com'), array('name'=>'Treasure Porth', 'email'=> 'treasure.porth@teamtreehouse.com'), array('name'=>'Andrew Chalkley', 'email'=> 'andrew.chalkley@teamtreehouse.com') );
echo "<ul>\n"; //$contacts[0] will return 'Alena Holligan' in our simple array of names. echo "<li>" . $contacts[0]['name'] . " : " . $contacts[0]['email'] . "</li>\n"; echo "<li>" . $contacts[1]['name'] . " : " . $contacts[1]['email'] . "</li>\n"; echo "<li>" . $contacts[2]['name'] . " : " . $contacts[2]['email'] . "</li>\n"; echo "<li>" . $contacts[3]['name'] . " : " . $contacts[3]['email'] . "</li>\n"; echo "</ul>\n";
I think it might be in the way you are building to array --$Alena = array('name'-- where mine omits the $Alena =
I hope this helps
tylerduprey
Full Stack JavaScript Techdegree Student 25,399 PointsThat did it! Thanks Mike.
Dmitriy Davydov
8,768 PointsDmitriy Davydov
8,768 PointsHi. I had a similar problem also on PHP track (but with other task). I think the problem is within the logic of the program which is checking up the solutions, a kind of that.