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Start your free trialAdrian Torrente Tenreiro
12,540 PointsIm completely stuck here.
Im basically going through all the characters
Am i missing something?
public class ScrabblePlayer
{
// A String representing all of the tiles that this player has
private String tiles;
public ScrabblePlayer()
{
tiles = "";
}
public String getTiles()
{
return tiles;
}
public void addTile(char tile)
{
tiles += tile;
}
public boolean hasTile(char tile)
{
return tiles.indexOf(tile) != -1;
}
private int counter;
public int getCountOfLetter(char letter)
{
for(int i=0; i<tiles.length(); i++)
{
if(tiles.toCharArray(i) == letter )
{
counter++;
}
}
}
return counter;
}
}
// This code is here for example purposes only
public class Example {
public static void main(String[] args) {
ScrabblePlayer player1 = new ScrabblePlayer();
player1.addTile('d');
player1.addTile('d');
player1.addTile('p');
player1.addTile('e');
player1.addTile('l');
player1.addTile('u');
ScrabblePlayer player2 = new ScrabblePlayer();
player2.addTile('z');
player2.addTile('z');
player2.addTile('y');
player2.addTile('f');
player2.addTile('u');
player2.addTile('z');
int count = 0;
// This would set count to 1 because player1 has 1 'p' tile in her collection of tiles
count = player1.getCountOfLetter('p');
// This would set count to 2 because player1 has 2 'd'' tiles in her collection of tiles
count = player1.getCountOfLetter('d');
// This would set 0, because there isn't an 'a' tile in player1's tiles
count = player1.getCountOfLetter('a');
// This will return 3 because player2 has 3 'z' tiles in his collection of tiles
count = player2.getCountOfLetter('z');
// This will return 1 because player2 has 1 'f' tiles in his collection of tiles
count = player2.getCountOfLetter('f');
}
}
1 Answer
james south
Front End Web Development Techdegree Graduate 33,271 Pointsi think you want to convert to charArray before the for loop and then loop through that, so that your loop variable is a char in the array and can then be compared to letter. also you seem to have an extra } in there above the return.