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iOS Protocols in Swift Creating Flexible Objects Using Protocols Swift's Standard Library Protocols

Chris Hinton
PLUS
Chris Hinton
Courses Plus Student 12,588 Points

I was able to say "user == anotherUser" by only conforming to Equatable (before implementing the == function). How?

My code is below.

The line user == anotherUser returned true, and if I changed the address in anotherUser it then returned false. So it looks like it was checking equality on all the stored properties. How did that work if I'd never implemented the == function in my struct?

Thanks.

struct User: PrettyPrintable, Equatable {
    let name: String
    let age: Int
    let address: String    

    func description() -> String {
        return "\(name), \(age), \(address)"
    }

    func prettyDescription() -> String {
        return "Name: \(name),\nAge: \(age),\nAddress: \(address)"
    }
}

let user = User(name: "Chris", age: 41, address: "My Address")
let anotherUser = User(name: "Chris", age: 41, address: "My Address")

user == anotherUser

1 Answer

Jennifer Nordell
seal-mask
STAFF
.a{fill-rule:evenodd;}techdegree
Jennifer Nordell
Treehouse Teacher

Hi, Chris Hinton ! As I understand it, the Equatable protocol checks through every property to see if the values match by default. The use of the == function is there if you want to customize what you're checking for in some way. I might suggest taking a look at the Apple Developer documentation on the Equatable protocol here.

This excerpt is particularly interesting in this case.

To customize your type’s Equatable conformance, to adopt Equatable in a type that doesn’t meet the criteria listed above, or to extend an existing type to conform to Equatable, implement the equal-to operator (==) as a static method of your type. The standard library provides an implementation for the not-equal-to operator (!=) for any Equatable type, which calls the custom == function and negates its result.

Hope this helps! :sparkles: