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Android Build an Interactive Story App (Retired) Finishing the User Interface Using a Model in the Controller

I thought I did attach the code. Sorry. Where and how am I supposed to pass the string?

Please help ASAP

Kevin Faust
Kevin Faust
15,353 Points

can you please post your code

import android.os.Bundle; import android.view.View; import android.widget.Button; import android.widget.EditText;

public class LandingActivity extends Activity {

public Button mThrustButton;
public TextView mTypeLabel;
public EditText mPassengersField;

public Spaceship mSpaceship;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_landing);

    mThrustButton = (Button)findViewById(R.id.thrustButton);
    mTypeLabel = (TextView)findViewById(R.id.typeTextView);
    mPassengersField = (EditText)findViewById(R.id.passengersEditText);

    // Add your code here!
}

}

The LandingActivity interacts with the Spaceship model object we created. Start by setting mSpaceship to a new Spaceship object in the onCreate() method. Use the custom constructor that takes a String parameter, and pass in "FIREFLY" as the parameter.

This is the question

Thanks Kevin.

1 Answer

Kevin Faust
Kevin Faust
15,353 Points

All you do is add this right below where it says // Add your code here!:

 mSpaceship = new Spaceship("FIREFLY");

We are simply creating a new Spaceship object and passing it a string as a paramter. As written in the instructions, we pass in "FIREFLY" as a paramater