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Java Java Arrays Creation Create an array literal

Posted by yared sisay
yared sisay
98 Points

I need help with the java arrays literal method of the exercise. it did not work for me I don't know why?

the literal method should work if when I give it the array value . String [] teachers = {"LIST1","LIST2","LIST3"}; THIS IS NOT works for me so is there any problems on IDE

TeachersExample.java 
public class TeachersExample {

  public String[] getTeachersInArrayLongForm() {
    String[] teachers = new String[null];
    teachers[0] = "Jay";
    teachers[1] = "Dave";
    teachers[2] = "James";
    return teachers;
  }

  public String[] getTeachersAsArrayLiteral() {
    // TODO: Replace null with an array literal that matches the long form above
    String[] teachers;
    String teachers = new String[] {"Jay","Dave","James"};
    return teachers;
  }

}

1 Answer

Alex Kennedy
Alex Kennedy
2,073 Points
Alex Kennedy
Alex Kennedy
2,073 Points

You do not need to cast the teachers array of Strings to a String variable.

public String[] getTeachersAsArrayLiteral() {
    String[] teachers = {"Jay", "Dave", "James"};
    return teachers;
  }

This works.

r j weiner
r j weiner
2,741 Points

nice